At first, Containers Q, R and S contained water as shown. Some water from Containers R and S was poured into Container Q without any spilling over. The volume of water left in Containers R and S is shown. What would be the volume of water in Container Q?
2 ℓ = 2000 mℓ

Volume of water at each division on Container Q
= 2000 ÷ 10
= 200 mℓ

Volume of water in Container Q at first
= 6 x 200
= 1200 mℓ

Volume of water at each division on Container R
= 800 ÷ 10
= 80 mℓ

Volume of water in Container R
= 8 x 80
= 640 mℓ

Volume of water at each division in Container S
= 500 ÷ 10
= 50 mℓ

Amount of water contained in Container S
= 9 x 50
= 450 mℓ

Total volume of water in Container R and Container S
= 640 + 450
= 1090 mℓ

Volume of water in Container R after pouring
= 6 x 80
= 480 mℓ

Volume of water in Container S after pouring
= 6 x 50
= 300 mℓ

Volume of water in Container R and Container S
= 480 + 300
= 780 mℓ

Volume of water poured in Container Q
= 1090 - 780
= 310 mℓ

Total volume of water in Container Q
= 1200 + 310
= 1510 mℓ

Answer(s): 1510 mℓ