At first, Containers N, P and Q contained water as shown. Some water from Containers P and Q was poured into Container N without any spilling over. The volume of water left in Containers P and Q is shown. What would be the volume of water in Container N?
2 ℓ = 2000 mℓ

Volume of water at each division on Container N
= 2000 ÷ 10
= 200 mℓ

Volume of water in Container N at first
= 6 x 200
= 1200 mℓ

Volume of water at each division on Container P
= 900 ÷ 10
= 90 mℓ

Volume of water in Container P
= 8 x 90
= 720 mℓ

Volume of water at each division in Container Q
= 600 ÷ 10
= 60 mℓ

Amount of water contained in Container Q
= 9 x 60
= 540 mℓ

Total volume of water in Container P and Container Q
= 720 + 540
= 1260 mℓ

Volume of water in Container P after pouring
= 6 x 90
= 540 mℓ

Volume of water in Container Q after pouring
= 6 x 60
= 360 mℓ

Volume of water in Container P and Container Q
= 540 + 360
= 900 mℓ

Volume of water poured in Container N
= 1260 - 900
= 360 mℓ

Total volume of water in Container N
= 1200 + 360
= 1560 mℓ

Answer(s): 1560 mℓ