At first, Containers C, D and E contained water as shown. Some water from Containers D and E was poured into Container C without any spilling over. The volume of water left in Containers D and E is shown. What would be the volume of water in Container C?
2 ℓ = 2000 mℓ

Volume of water at each division on Container C
= 2000 ÷ 10
= 200 mℓ

Volume of water in Container C at first
= 6 x 200
= 1200 mℓ

Volume of water at each division on Container D
= 900 ÷ 10
= 90 mℓ

Volume of water in Container D
= 8 x 90
= 720 mℓ

Volume of water at each division in Container E
= 500 ÷ 10
= 50 mℓ

Amount of water contained in Container E
= 9 x 50
= 450 mℓ

Total volume of water in Container D and Container E
= 720 + 450
= 1170 mℓ

Volume of water in Container D after pouring
= 6 x 90
= 540 mℓ

Volume of water in Container E after pouring
= 6 x 50
= 300 mℓ

Volume of water in Container D and Container E
= 540 + 300
= 840 mℓ

Volume of water poured in Container C
= 1170 - 840
= 330 mℓ

Total volume of water in Container C
= 1200 + 330
= 1530 mℓ

Answer(s): 1530 mℓ