At first, Containers P, Q and R contained water as shown. Some water from Containers Q and R was poured into Container P without any spilling over. The volume of water left in Containers Q and R is shown. What would be the volume of water in Container P?
2 ℓ = 2000 mℓ

Volume of water at each division on Container P
= 2000 ÷ 10
= 200 mℓ

Volume of water in Container P at first
= 6 x 200
= 1200 mℓ

Volume of water at each division on Container Q
= 900 ÷ 10
= 90 mℓ

Volume of water in Container Q
= 8 x 90
= 720 mℓ

Volume of water at each division in Container R
= 700 ÷ 10
= 70 mℓ

Amount of water contained in Container R
= 9 x 70
= 630 mℓ

Total volume of water in Container Q and Container R
= 720 + 630
= 1350 mℓ

Volume of water in Container Q after pouring
= 6 x 90
= 540 mℓ

Volume of water in Container R after pouring
= 6 x 70
= 420 mℓ

Volume of water in Container Q and Container R
= 540 + 420
= 960 mℓ

Volume of water poured in Container P
= 1350 - 960
= 390 mℓ

Total volume of water in Container P
= 1200 + 390
= 1590 mℓ

Answer(s): 1590 mℓ