A rectangular container measuring 88 cm by 51 cm by 39 cm was to be filled with water by two taps, R and S. Tap R which fills the tank at a rate of 8 ℓ per minute was first turned on for 4 minutes before Tap S was turned on as well. If the tank was filled to the brim in a total of 6 minutes from the time when Tap R was first turned on, what is the rate at which Tap S fills the tank? Give your answer in ℓ per minute correct to 1 decimal place.
Total volume of the container
= 88 x 51 x 39
= 175032 cm
3 1 ℓ = 1000 cm
3 8 ℓ = 8000 cm
3 Volume of water filled by Tap R
= 8000 x 6
= 48000 cm
3 Volume of water filled by Tap S
= 175032 - 48000
= 127032 cm
3 Rate in which Tap S fills the container
= 127032 ÷ 2
= 63516 cm3/min
63516 mℓ/min
= 63.516 ℓ/min
≈ 63.5 ℓ/min (Correct to 1 decimal place)
Answer(s): 63.5 ℓ/min