A rectangular container measuring 76 cm by 51 cm by 28 cm was to be filled with water by two taps, U and V. Tap U which fills the tank at a rate of 6 ℓ per minute was first turned on for 4 minutes before Tap V was turned on as well. If the tank was filled to the brim in a total of 6 minutes from the time when Tap U was first turned on, what is the rate at which Tap V fills the tank? Give your answer in ℓ per minute correct to 1 decimal place.
Total volume of the container
= 76 x 51 x 28
= 108528 cm
3 1 ℓ = 1000 cm
3 6 ℓ = 6000 cm
3 Volume of water filled by Tap U
= 6000 x 6
= 36000 cm
3 Volume of water filled by Tap V
= 108528 - 36000
= 72528 cm
3 Rate in which Tap V fills the container
= 72528 ÷ 2
= 36264 cm3/min
36264 mℓ/min
= 36.264 ℓ/min
≈ 36.3 ℓ/min (Correct to 1 decimal place)
Answer(s): 36.3 ℓ/min