A rectangular container measuring 76 cm by 60 cm by 26 cm was to be filled with water by two taps, G and H. Tap G which fills the tank at a rate of 6 ℓ per minute was first turned on for 3 minutes before Tap H was turned on as well. If the tank was filled to the brim in a total of 6 minutes from the time when Tap G was first turned on, what is the rate at which Tap H fills the tank? Give your answer in ℓ per minute correct to 1 decimal place.
Total volume of the container
= 76 x 60 x 26
= 118560 cm
3 1 ℓ = 1000 cm
3 6 ℓ = 6000 cm
3 Volume of water filled by Tap G
= 6000 x 6
= 36000 cm
3 Volume of water filled by Tap H
= 118560 - 36000
= 82560 cm
3 Rate in which Tap H fills the container
= 82560 ÷ 3
= 27520 cm3/min
27520 mℓ/min
= 27.52 ℓ/min
≈ 27.5 ℓ/min (Correct to 1 decimal place)
Answer(s): 27.5 ℓ/min