A rectangular container measuring 80 cm by 53 cm by 40 cm was to be filled with water by two taps, S and T. Tap S which fills the tank at a rate of 5 ℓ per minute was first turned on for 4 minutes before Tap T was turned on as well. If the tank was filled to the brim in a total of 6 minutes from the time when Tap S was first turned on, what is the rate at which Tap T fills the tank? Give your answer in ℓ per minute correct to 1 decimal place.
Total volume of the container
= 80 x 53 x 40
= 169600 cm
3 1 ℓ = 1000 cm
3 5 ℓ = 5000 cm
3 Volume of water filled by Tap S
= 5000 x 6
= 30000 cm
3 Volume of water filled by Tap T
= 169600 - 30000
= 139600 cm
3 Rate in which Tap T fills the container
= 139600 ÷ 2
= 69800 cm3/min
69800 mℓ/min
= 69.8 ℓ/min
≈ 69.8 ℓ/min (Correct to 1 decimal place)
Answer(s): 69.8 ℓ/min