A rectangular container measuring 71 cm by 52 cm by 24 cm was to be filled with water by two taps, S and T. Tap S which fills the tank at a rate of 6 ℓ per minute was first turned on for 3 minutes before Tap T was turned on as well. If the tank was filled to the brim in a total of 7 minutes from the time when Tap S was first turned on, what is the rate at which Tap T fills the tank? Give your answer in ℓ per minute correct to 1 decimal place.
Total volume of the container
= 71 x 52 x 24
= 88608 cm
3 1 ℓ = 1000 cm
3 6 ℓ = 6000 cm
3 Volume of water filled by Tap S
= 6000 x 7
= 42000 cm
3 Volume of water filled by Tap T
= 88608 - 42000
= 46608 cm
3 Rate in which Tap T fills the container
= 46608 ÷ 4
= 11652 cm3/min
11652 mℓ/min
= 11.652 ℓ/min
≈ 11.7 ℓ/min (Correct to 1 decimal place)
Answer(s): 11.7 ℓ/min