S and T are two rectangular tanks. The base area of S is 96 cm
2 while that of T is 48 cm
2 . At first, S contained water to a height of 58 cm and T was empty, as shown.
- What was the volume of the water in S at first?
- Perry then poured some water from S to T. After that, the height of the water level in S was twice that in T. What was the new height of the water level in S?
(a)
Volume of water in S
= 96 x 58
= 5568 cm
3 (b)
Total base areas
= 96 + 96 + 48
= 240 cm
2 Height of water if the total base area is 240 cm
2 = 5568 ÷ 240
= 23.2 cm
New height of the water level in S
= 23.2 x 2
= 46.4 cm
Answer(s): (a) 5568 cm
3; (b) 46.4 cm