S and T are two rectangular containers. The base area of S is 96 cm
2 while that of T is 32 cm
2 . At first, S contained water to a height of 44 cm and T was empty, as shown.
- What was the volume of the water in S at first?
- Fred then poured some water from S to T. After that, the height of the water level in S was thrice that in T. What was the new height of the water level in S?
(a)
Volume of water in S
= 96 x 44
= 4224 cm
3 (b)
Total base areas
= 96 x 3 + 32
= 320 cm
2 Height of water if the total base area is 320 cm
2 = 4224 ÷ 320
= 13.2 cm
New height of the water level in S
= 13.2 x 3
= 39.6 cm
Answer(s): (a) 4224 cm
3; (b) 39.6 cm