L and M are two rectangular containers. The base area of L is 81 cm
2 while that of M is 38 cm
2 . At first, L contained water to a height of 40 cm and M was empty, as shown.
- What was the volume of the water in L at first?
- Sam then poured some water from L to M. After that, the height of the water level in L was twice that in M. What was the new height of the water level in L?
(a)
Volume of water in L
= 81 x 40
= 3240 cm
3 (b)
Total base areas
= 81 + 81 + 38
= 200 cm
2 Height of water if the total base area is 200 cm
2 = 3240 ÷ 200
= 16.2 cm
New height of the water level in L
= 16.2 x 2
= 32.4 cm
Answer(s): (a) 3240 cm
3; (b) 32.4 cm