N and P are two rectangular tanks. The base area of N is 94 cm
2 while that of P is 38 cm
2 . At first, N contained water to a height of 48 cm and P was empty, as shown.
- What was the volume of the water in N at first?
- Gabriel then poured some water from N to P. After that, the height of the water level in N was thrice that in P. What was the new height of the water level in N?
(a)
Volume of water in N
= 94 x 48
= 4512 cm
3 (b)
Total base areas
= 94 x 3 + 38
= 320 cm
2 Height of water if the total base area is 320 cm
2 = 4512 ÷ 320
= 14.1 cm
New height of the water level in N
= 14.1 x 3
= 42.3 cm
Answer(s): (a) 4512 cm
3; (b) 42.3 cm