R and S are two rectangular containers. The base area of R is 96 cm
2 while that of S is 32 cm
2 . At first, R contained water to a height of 42 cm and S was empty, as shown.
- What was the volume of the water in R at first?
- Gabriel then poured some water from R to S. After that, the height of the water level in R was thrice that in S. What was the new height of the water level in R?
(a)
Volume of water in R
= 96 x 42
= 4032 cm
3 (b)
Total base areas
= 96 x 3 + 32
= 320 cm
2 Height of water if the total base area is 320 cm
2 = 4032 ÷ 320
= 12.6 cm
New height of the water level in R
= 12.6 x 3
= 37.8 cm
Answer(s): (a) 4032 cm
3; (b) 37.8 cm