N and P are two rectangular containers. The base area of N is 77 cm
2 while that of P is 49 cm
2 . At first, N contained water to a height of 36 cm and P was empty, as shown.
- What was the volume of the water in N at first?
- Sam then poured some water from N to P. After that, the height of the water level in N was thrice that in P. What was the new height of the water level in N?
(a)
Volume of water in N
= 77 x 36
= 2772 cm
3 (b)
Total base areas
= 77 x 3 + 49
= 280 cm
2 Height of water if the total base area is 280 cm
2 = 2772 ÷ 280
= 9.9 cm
New height of the water level in N
= 9.9 x 3
= 29.7 cm
Answer(s): (a) 2772 cm
3; (b) 29.7 cm