L and M are two rectangular containers. The base area of L is 98 cm
2 while that of M is 44 cm
2 . At first, L contained water to a height of 36 cm and M was empty, as shown.
- What was the volume of the water in L at first?
- Luis then poured some water from L to M. After that, the height of the water level in L was twice that in M. What was the new height of the water level in L?
(a)
Volume of water in L
= 98 x 36
= 3528 cm
3 (b)
Total base areas
= 98 + 98 + 44
= 240 cm
2 Height of water if the total base area is 240 cm
2 = 3528 ÷ 240
= 14.7 cm
New height of the water level in L
= 14.7 x 2
= 29.4 cm
Answer(s): (a) 3528 cm
3; (b) 29.4 cm