N and P are two rectangular tanks. The base area of N is 76 cm
2 while that of P is 38 cm
2 . At first, N contained water to a height of 54 cm and P was empty, as shown.
- What was the volume of the water in N at first?
- Bobby then poured some water from N to P. After that, the height of the water level in N was twice that in P. What was the new height of the water level in N?
(a)
Volume of water in N
= 76 x 54
= 4104 cm
3 (b)
Total base areas
= 76 + 76 + 38
= 190 cm
2 Height of water if the total base area is 190 cm
2 = 4104 ÷ 190
= 21.6 cm
New height of the water level in N
= 21.6 x 2
= 43.2 cm
Answer(s): (a) 4104 cm
3; (b) 43.2 cm