L and M are two rectangular containers. The base area of L is 70 cm
2 while that of M is 36 cm
2 . At first, L contained water to a height of 55 cm and M was empty, as shown.
- What was the volume of the water in L at first?
- Ken then poured some water from L to M. After that, the height of the water level in L was twice that in M. What was the new height of the water level in L?
(a)
Volume of water in L
= 70 x 55
= 3850 cm
3 (b)
Total base areas
= 70 + 70 + 36
= 176 cm
2 Height of water if the total base area is 176 cm
2 = 3850 ÷ 176
= 21.875 cm
New height of the water level in L
= 21.875 x 2
= 43.75 cm
Answer(s): (a) 3850 cm
3; (b) 43.75 cm