N and P are two rectangular containers. The base area of N is 92 cm
2 while that of P is 44 cm
2 . At first, N contained water to a height of 38 cm and P was empty, as shown.
- What was the volume of the water in N at first?
- Will then poured some water from N to P. After that, the height of the water level in N was thrice that in P. What was the new height of the water level in N?
(a)
Volume of water in N
= 92 x 38
= 3496 cm
3 (b)
Total base areas
= 92 x 3 + 44
= 320 cm
2 Height of water if the total base area is 320 cm
2 = 3496 ÷ 320
= 10.925 cm
New height of the water level in N
= 10.925 x 3
= 32.775 cm
Answer(s): (a) 3496 cm
3; (b) 32.775 cm