L and M are two rectangular tanks. The base area of L is 76 cm
2 while that of M is 38 cm
2 . At first, L contained water to a height of 56 cm and M was empty, as shown.
- What was the volume of the water in L at first?
- Oliver then poured some water from L to M. After that, the height of the water level in L was thrice that in M. What was the new height of the water level in L?
(a)
Volume of water in L
= 76 x 56
= 4256 cm
3 (b)
Total base areas
= 76 x 3 + 38
= 266 cm
2 Height of water if the total base area is 266 cm
2 = 4256 ÷ 266
= 16 cm
New height of the water level in L
= 16 x 3
= 48 cm
Answer(s): (a) 4256 cm
3; (b) 48 cm