L and M are two rectangular containers. The base area of L is 78 cm
2 while that of M is 44 cm
2 . At first, L contained water to a height of 57 cm and M was empty, as shown.
- What was the volume of the water in L at first?
- Paul then poured some water from L to M. After that, the height of the water level in L was twice that in M. What was the new height of the water level in L?
(a)
Volume of water in L
= 78 x 57
= 4446 cm
3 (b)
Total base areas
= 78 + 78 + 44
= 200 cm
2 Height of water if the total base area is 200 cm
2 = 4446 ÷ 200
= 22.23 cm
New height of the water level in L
= 22.23 x 2
= 44.46 cm
Answer(s): (a) 4446 cm
3; (b) 44.46 cm