S and T are two rectangular containers. The base area of S is 86 cm
2 while that of T is 42 cm
2 . At first, S contained water to a height of 60 cm and T was empty, as shown.
- What was the volume of the water in S at first?
- Bobby then poured some water from S to T. After that, the height of the water level in S was thrice that in T. What was the new height of the water level in S?
(a)
Volume of water in S
= 86 x 60
= 5160 cm
3 (b)
Total base areas
= 86 x 3 + 42
= 300 cm
2 Height of water if the total base area is 300 cm
2 = 5160 ÷ 300
= 17.2 cm
New height of the water level in S
= 17.2 x 3
= 51.6 cm
Answer(s): (a) 5160 cm
3; (b) 51.6 cm