Q and R are two rectangular tanks. The base area of Q is 96 cm
2 while that of R is 40 cm
2 . At first, Q contained water to a height of 58 cm and R was empty, as shown.
- What was the volume of the water in Q at first?
- Tom then poured some water from Q to R. After that, the height of the water level in Q was twice that in R. What was the new height of the water level in Q?
(a)
Volume of water in Q
= 96 x 58
= 5568 cm
3 (b)
Total base areas
= 96 + 96 + 40
= 232 cm
2 Height of water if the total base area is 232 cm
2 = 5568 ÷ 232
= 24 cm
New height of the water level in Q
= 24 x 2
= 48 cm
Answer(s): (a) 5568 cm
3; (b) 48 cm