M and N are two rectangular tanks. The base area of M is 90 cm
2 while that of N is 30 cm
2 . At first, M contained water to a height of 56 cm and N was empty, as shown.
- What was the volume of the water in M at first?
- Luke then poured some water from M to N. After that, the height of the water level in M was thrice that in N. What was the new height of the water level in M?
(a)
Volume of water in M
= 90 x 56
= 5040 cm
3 (b)
Total base areas
= 90 x 3 + 30
= 300 cm
2 Height of water if the total base area is 300 cm
2 = 5040 ÷ 300
= 16.8 cm
New height of the water level in M
= 16.8 x 3
= 50.4 cm
Answer(s): (a) 5040 cm
3; (b) 50.4 cm