M and N are two rectangular containers. The base area of M is 93 cm
2 while that of N is 31 cm
2 . At first, M contained water to a height of 41 cm and N was empty, as shown.
- What was the volume of the water in M at first?
- David then poured some water from M to N. After that, the height of the water level in M was thrice that in N. What was the new height of the water level in M?
(a)
Volume of water in M
= 93 x 41
= 3813 cm
3 (b)
Total base areas
= 93 x 3 + 31
= 310 cm
2 Height of water if the total base area is 310 cm
2 = 3813 ÷ 310
= 12.3 cm
New height of the water level in M
= 12.3 x 3
= 36.9 cm
Answer(s): (a) 3813 cm
3; (b) 36.9 cm