N and P are two rectangular containers. The base area of N is 91 cm
2 while that of P is 38 cm
2 . At first, N contained water to a height of 44 cm and P was empty, as shown.
- What was the volume of the water in N at first?
- Henry then poured some water from N to P. After that, the height of the water level in N was twice that in P. What was the new height of the water level in N?
(a)
Volume of water in N
= 91 x 44
= 4004 cm
3 (b)
Total base areas
= 91 + 91 + 38
= 220 cm
2 Height of water if the total base area is 220 cm
2 = 4004 ÷ 220
= 18.2 cm
New height of the water level in N
= 18.2 x 2
= 36.4 cm
Answer(s): (a) 4004 cm
3; (b) 36.4 cm