N and P are two rectangular containers. The base area of N is 92 cm
2 while that of P is 46 cm
2 . At first, N contained water to a height of 37 cm and P was empty, as shown.
- What was the volume of the water in N at first?
- Gabriel then poured some water from N to P. After that, the height of the water level in N was twice that in P. What was the new height of the water level in N?
(a)
Volume of water in N
= 92 x 37
= 3404 cm
3 (b)
Total base areas
= 92 + 92 + 46
= 230 cm
2 Height of water if the total base area is 230 cm
2 = 3404 ÷ 230
= 14.8 cm
New height of the water level in N
= 14.8 x 2
= 29.6 cm
Answer(s): (a) 3404 cm
3; (b) 29.6 cm