The figure shows a container made up of 3 sections. Cuboid W with a square base of side 25 cm and height 37 cm. Cube X with a side of 10 cm. Cuboid Y that is 70 cm by 18 cm by 45 cm. Water from a tap above flows down at a rate of 2.6 litres per minute while water is drained out from the bottom at a rate of 2 litre per minute. How long did it take to fill up the container to a height of 64 cm from the base? Give the answer in minutes correct to nearest whole number.
Volume of X
= 10 x 10 x 10
= 1000 cm³ 

Volume of Y
= 70 x 18 x 45
= 56700 cm³ 

2 ℓ = 2000 cm³ 
2.6 ℓ = 2600 cm³ 

Net increase in volume per minute
= 2600 - 2000
= 600 cm³/min

Height of W to be filled with water
= 64 - (45 + 10)
= 9 cm

Volume of water in W
= 25 x 25 x 9
= 5625 cm³ 

Volume of water in Y, X and part of W
= 56700 + 1000 + 5625
= 63325 cm³ 

Time taken to reach height
= 63325 ÷ 600
≈ 106 min (Correct to nearest whole number)

Answer(s): 106 min