The figure shows a container made up of 3 sections. Cuboid A with a square base of side 14 cm and height 33 cm. Cube B with a side of 12 cm. Cuboid C that is 63 cm by 20 cm by 44 cm. Water from a tap above flows down at a rate of 2.3 litres per minute while water is drained out from the bottom at a rate of 2 litre per minute. How long did it take to fill up the container to a height of 63 cm from the base? Give the answer in minutes correct to nearest whole number.
Volume of B
= 12 x 12 x 12
= 1728 cm³ 

Volume of C
= 63 x 20 x 44
= 55440 cm³ 

2 ℓ = 2000 cm³ 
2.3 ℓ = 2300 cm³ 

Net increase in volume per minute
= 2300 - 2000
= 300 cm³/min

Height of A to be filled with water
= 63 - (44 + 12)
= 7 cm

Volume of water in A
= 14 x 14 x 7
= 1372 cm³ 

Volume of water in C, B and part of A
= 55440 + 1728 + 1372
= 58540 cm³ 

Time taken to reach height
= 58540 ÷ 300
≈ 195 min (Correct to nearest whole number)

Answer(s): 195 min