Tank S, measuring 80 cm by 25 cm by 63 cm, was filled with water to the brim. Water was then poured from Tank S to Tank T, which has a base area of 440 cm² until the height of the water level in Tank T became twice that of the water level in Tank S. Find the volume of water in Tank T, leaving your answer in cubic cm.
Volume of Tank S
= 80 x 25 x 63
= 126000 cm³ 

Base area of Tank S 
= 80 x 25
= 2000 cm²

Total base areas
= 2000 + 440 + 440
= 2880 cm² 

Height of the water level in Tank S after pouring
= 126000 ÷ 2880
= 43.75 cm

Height of the water level in Tank T after pouring
= 2 x 43.75 
= 87.5 cm

Volume of water in Tank T
= 440 x 87.5
= 38500 cm³ 

Answer(s): 38500 cm³