Container M, measuring 75 cm by 20 cm by 59 cm, was filled with water to the brim. Water was then poured from Container M to Container N, which has a base area of 500 cm² until the height of the water level in Container N became thrice that of the water level in Container M. Find the volume of water in Container N, leaving your answer in cubic cm.
Volume of Container M
= 75 x 20 x 59
= 88500 cm³ 

Base area of Container M 
= 75 x 20
= 1500 cm²

Total base areas
= 1500 + 500 + 500 + 500
= 3000 cm² 

Height of the water level in Container M after pouring
= 88500 ÷ 3000
= 29.5 cm

Height of the water level in Container N after pouring
= 3 x 29.5 
= 88.5 cm

Volume of water in Container N
= 500 x 88.5
= 44250 cm³ 

Answer(s): 44250 cm³