Tank L, measuring 60 cm by 40 cm by 61 cm, was filled with water to the brim. Water was then poured from Tank L to Tank M, which has a base area of 420 cm² until the height of the water level in Tank M became thrice that of the water level in Tank L. Find the volume of water in Tank M, leaving your answer in cubic cm.
Volume of Tank L
= 60 x 40 x 61
= 146400 cm³ 

Base area of Tank L 
= 60 x 40
= 2400 cm²

Total base areas
= 2400 + 420 + 420 + 420
= 3660 cm² 

Height of the water level in Tank L after pouring
= 146400 ÷ 3660
= 40 cm

Height of the water level in Tank M after pouring
= 3 x 40 
= 120 cm

Volume of water in Tank M
= 420 x 120
= 50400 cm³ 

Answer(s): 50400 cm³