Container N, measuring 45 cm by 20 cm by 52 cm, was filled with water to the brim. Water was then poured from Container N to Container P, which has a base area of 798 cm² until the height of the water level in Container P became twice that of the water level in Container N. Find the volume of water in Container P, leaving your answer in cubic cm.
Volume of Container N
= 45 x 20 x 52
= 46800 cm³ 

Base area of Container N 
= 45 x 20
= 900 cm²

Total base areas
= 900 + 798 + 798
= 2496 cm² 

Height of the water level in Container N after pouring
= 46800 ÷ 2496
= 18.75 cm

Height of the water level in Container P after pouring
= 2 x 18.75 
= 37.5 cm

Volume of water in Container P
= 798 x 37.5
= 29925 cm³ 

Answer(s): 29925 cm³