Container S, measuring 50 cm by 40 cm by 62 cm, was filled with water to the brim. Water was then poured from Container S to Container T, which has a base area of 984 cm² until the height of the water level in Container T became twice that of the water level in Container S. Find the volume of water in Container T, leaving your answer in cubic cm.
Volume of Container S
= 50 x 40 x 62
= 124000 cm³ 

Base area of Container S 
= 50 x 40
= 2000 cm²

Total base areas
= 2000 + 984 + 984
= 3968 cm² 

Height of the water level in Container S after pouring
= 124000 ÷ 3968
= 31.25 cm

Height of the water level in Container T after pouring
= 2 x 31.25 
= 62.5 cm

Volume of water in Container T
= 984 x 62.5
= 61500 cm³ 

Answer(s): 61500 cm³