Container M, measuring 80 cm by 30 cm by 33 cm, was filled with water to the brim. Water was then poured from Container M to Container N, which has a base area of 300 cm² until the height of the water level in Container N became thrice that of the water level in Container M. Find the volume of water in Container N, leaving your answer in cubic cm.
Volume of Container M
= 80 x 30 x 33
= 79200 cm³ 

Base area of Container M 
= 80 x 30
= 2400 cm²

Total base areas
= 2400 + 300 + 300 + 300
= 3300 cm² 

Height of the water level in Container M after pouring
= 79200 ÷ 3300
= 24 cm

Height of the water level in Container N after pouring
= 3 x 24 
= 72 cm

Volume of water in Container N
= 300 x 72
= 21600 cm³ 

Answer(s): 21600 cm³