Tank S, measuring 80 cm by 20 cm by 35 cm, was filled with water to the brim. Water was then poured from Tank S to Tank T, which has a base area of 960 cm² until the height of the water level in Tank T became thrice that of the water level in Tank S. Find the volume of water in Tank T, leaving your answer in cubic cm.
Volume of Tank S
= 80 x 20 x 35
= 56000 cm³ 

Base area of Tank S 
= 80 x 20
= 1600 cm²

Total base areas
= 1600 + 960 + 960 + 960
= 4480 cm² 

Height of the water level in Tank S after pouring
= 56000 ÷ 4480
= 12.5 cm

Height of the water level in Tank T after pouring
= 3 x 12.5 
= 37.5 cm

Volume of water in Tank T
= 960 x 37.5
= 36000 cm³ 

Answer(s): 36000 cm³