Container L, measuring 60 cm by 30 cm by 42 cm, was filled with water to the brim. Water was then poured from Container L to Container M, which has a base area of 300 cm² until the height of the water level in Container M became twice that of the water level in Container L. Find the volume of water in Container M, leaving your answer in cubic cm.
Volume of Container L
= 60 x 30 x 42
= 75600 cm³ 

Base area of Container L 
= 60 x 30
= 1800 cm²

Total base areas
= 1800 + 300 + 300
= 2400 cm² 

Height of the water level in Container L after pouring
= 75600 ÷ 2400
= 31.5 cm

Height of the water level in Container M after pouring
= 2 x 31.5 
= 63 cm

Volume of water in Container M
= 300 x 63
= 18900 cm³ 

Answer(s): 18900 cm³