Container L, measuring 45 cm by 40 cm by 48 cm, was filled with water to the brim. Water was then poured from Container L to Container M, which has a base area of 650 cm² until the height of the water level in Container M became thrice that of the water level in Container L. Find the volume of water in Container M, leaving your answer in cubic cm.
Volume of Container L
= 45 x 40 x 48
= 86400 cm³ 

Base area of Container L 
= 45 x 40
= 1800 cm²

Total base areas
= 1800 + 650 + 650 + 650
= 3750 cm² 

Height of the water level in Container L after pouring
= 86400 ÷ 3750
= 23.04 cm

Height of the water level in Container M after pouring
= 3 x 23.04 
= 69.12 cm

Volume of water in Container M
= 650 x 69.12
= 44928 cm³ 

Answer(s): 44928 cm³