Container S, measuring 45 cm by 40 cm by 53 cm, was filled with water to the brim. Water was then poured from Container S to Container T, which has a base area of 600 cm² until the height of the water level in Container T became thrice that of the water level in Container S. Find the volume of water in Container T, leaving your answer in cubic cm.
Volume of Container S
= 45 x 40 x 53
= 95400 cm³ 

Base area of Container S 
= 45 x 40
= 1800 cm²

Total base areas
= 1800 + 600 + 600 + 600
= 3600 cm² 

Height of the water level in Container S after pouring
= 95400 ÷ 3600
= 26.5 cm

Height of the water level in Container T after pouring
= 3 x 26.5 
= 79.5 cm

Volume of water in Container T
= 600 x 79.5
= 47700 cm³ 

Answer(s): 47700 cm³