Container M, measuring 80 cm by 25 cm by 43 cm, was filled with water to the brim. Water was then poured from Container M to Container N, which has a base area of 1000 cm² until the height of the water level in Container N became twice that of the water level in Container M. Find the volume of water in Container N, leaving your answer in cubic cm.
Volume of Container M
= 80 x 25 x 43
= 86000 cm³ 

Base area of Container M 
= 80 x 25
= 2000 cm²

Total base areas
= 2000 + 1000 + 1000
= 4000 cm² 

Height of the water level in Container M after pouring
= 86000 ÷ 4000
= 21.5 cm

Height of the water level in Container N after pouring
= 2 x 21.5 
= 43 cm

Volume of water in Container N
= 1000 x 43
= 43000 cm³ 

Answer(s): 43000 cm³