The figure, not drawn to scale, is made of two connected cubical tanks, A and B. Tank A is sealed at the top and completely filled to the brim. Tank B is
34 filled with 194241 mℓ of water. The height of the water level in Tank B is 2 cm higher than that in Tank A. Height of Tank B is 68 cm. Water is then drained from the container and the height of the water level from the base falls to 37 cm.
- What is the capacity of Tank B in litres?
- What is the volume of water in the tank now in litres?
(a)
34 of Tank B = 194241 mℓ
14 of Tank B = 194241 ÷ 3 = 64747 mℓ
44 of Tank B = 64747 x 4 = 258988 mℓ
1 ℓ = 1000 mℓ
Capacity of Tank B = 258988 mℓ = 258.988 ℓ
(b)
Fraction of Tank B not filled
= 1 -
34 =
14 Height of Tank B not filled
=
14 x 68 cm
= 17 cm
Height of Tank A
= 68 - 17 - 2
= 49 cm
Volume of remaining water in Tank A
= 49 x 49 x 37
= 88837 cm
3 Volume of remaining water in Tank B
= 68 x 68 x 37
= 171088 cm
3 Total volume of remaining water in the tank
= 88837 + 171088
= 259925 cm
3
1 ℓ = 1000 cm
3 259925 cm
3 = 259.925 ℓ
Answer(s): (a) 258.988 ℓ; (b) 259.925 ℓ