The figure, not drawn to scale, is made of two connected cubical tanks, J and K. Tank J is sealed at the top and completely filled to the brim. Tank K is ²₅ filled with 110038 mℓ of water. The height of the water level in Tank K is 5 cm higher than that in Tank J. Height of Tank K is 70 cm. Water is then drained from the container and the height of the water level from the base falls to 37 cm.

1. What is the capacity of Tank K in litres?
2. What is the volume of water in the tank now in litres?

(a)
²₅ of Tank K = 110038 mℓ
¹₅ of Tank K = 110038 ÷ 2 = 55019 mℓ
⁵₅ of Tank K = 55019 x 5 = 275095 mℓ

1 ℓ = 1000 mℓ

Capacity of Tank K = 275095 mℓ = 275.095 ℓ

(b)
Fraction of Tank K not filled
= 1 - ²₅
= ³₅

Height of Tank K not filled
= ³₅ x 70 cm
= 42 cm

Height of Tank J
= 70 - 42 - 5
= 23 cm

Volume of remaining water in Tank J
= 23 x 23 x 37
= 19573 cm³ 

Volume of remaining water in Tank K
= 70 x 70 x 37
= 181300 cm³ 

Total volume of remaining water in the tank
= 19573 + 181300
= 200873 cm³

1 ℓ = 1000 cm³
200873 cm³ = 200.873 ℓ

Answer(s): (a) 275.095 ℓ; (b) 200.873 ℓ