The figure, not drawn to scale, is made of two connected cubical tanks, A and B. Tank A is sealed at the top and completely filled to the brim. Tank B is
35 filled with 121302 mℓ of water. The height of the water level in Tank B is 4 cm higher than that in Tank A. Height of Tank B is 70 cm. Water is then drained from the container and the height of the water level from the base falls to 24 cm.
- What is the capacity of Tank B in litres?
- What is the volume of water in the tank now in litres?
(a)
35 of Tank B = 121302 mℓ
15 of Tank B = 121302 ÷ 3 = 40434 mℓ
55 of Tank B = 40434 x 5 = 202170 mℓ
1 ℓ = 1000 mℓ
Capacity of Tank B = 202170 mℓ = 202.17 ℓ
(b)
Fraction of Tank B not filled
= 1 -
35 =
25 Height of Tank B not filled
=
25 x 70 cm
= 28 cm
Height of Tank A
= 70 - 28 - 4
= 38 cm
Volume of remaining water in Tank A
= 38 x 38 x 24
= 34656 cm
3 Volume of remaining water in Tank B
= 70 x 70 x 24
= 117600 cm
3 Total volume of remaining water in the tank
= 34656 + 117600
= 152256 cm
3
1 ℓ = 1000 cm
3 152256 cm
3 = 152.256 ℓ
Answer(s): (a) 202.17 ℓ; (b) 152.256 ℓ