The figure, not drawn to scale, is made of two connected cubical tanks, S and T. Tank S is sealed at the top and completely filled to the brim. Tank T is
23 filled with 139060 mℓ of water. The height of the water level in Tank T is 4 cm higher than that in Tank S. Height of Tank T is 69 cm. Water is then drained from the container and the height of the water level from the base falls to 38 cm.
- What is the capacity of Tank T in litres?
- What is the volume of water in the tank now in litres?
(a)
23 of Tank T = 139060 mℓ
13 of Tank T = 139060 ÷ 2 = 69530 mℓ
33 of Tank T = 69530 x 3 = 208590 mℓ
1 ℓ = 1000 mℓ
Capacity of Tank T = 208590 mℓ = 208.59 ℓ
(b)
Fraction of Tank T not filled
= 1 -
23 =
13 Height of Tank T not filled
=
13 x 69 cm
= 23 cm
Height of Tank S
= 69 - 23 - 4
= 42 cm
Volume of remaining water in Tank S
= 42 x 42 x 38
= 67032 cm
3 Volume of remaining water in Tank T
= 69 x 69 x 38
= 180918 cm
3 Total volume of remaining water in the tank
= 67032 + 180918
= 247950 cm
3
1 ℓ = 1000 cm
3 247950 cm
3 = 247.95 ℓ
Answer(s): (a) 208.59 ℓ; (b) 247.95 ℓ