The figure, not drawn to scale, is made of two connected cubical tanks, G and H. Tank G is sealed at the top and completely filled to the brim. Tank H is ⁴₅ filled with 125496 mℓ of water. The height of the water level in Tank H is 4 cm higher than that in Tank G. Height of Tank H is 60 cm. Water is then drained from the container and the height of the water level from the base falls to 35 cm.

1. What is the capacity of Tank H in litres?
2. What is the volume of water in the tank now in litres?

(a)
⁴₅ of Tank H = 125496 mℓ
¹₅ of Tank H = 125496 ÷ 4 = 31374 mℓ
⁵₅ of Tank H = 31374 x 5 = 156870 mℓ

1 ℓ = 1000 mℓ

Capacity of Tank H = 156870 mℓ = 156.87 ℓ

(b)
Fraction of Tank H not filled
= 1 - ⁴₅
= ¹₅

Height of Tank H not filled
= ¹₅ x 60 cm
= 12 cm

Height of Tank G
= 60 - 12 - 4
= 44 cm

Volume of remaining water in Tank G
= 44 x 44 x 35
= 67760 cm³ 

Volume of remaining water in Tank H
= 60 x 60 x 35
= 126000 cm³ 

Total volume of remaining water in the tank
= 67760 + 126000
= 193760 cm³

1 ℓ = 1000 cm³
193760 cm³ = 193.76 ℓ

Answer(s): (a) 156.87 ℓ; (b) 193.76 ℓ