The figure, not drawn to scale, is made of two connected cubical containers, K and L. Container K is sealed at the top and completely filled to the brim. Container L is
35 filled with 177615 mℓ of water. The height of the water level in Container L is 4 cm higher than that in Container K. Height of Container L is 70 cm. Water is then drained from the container and the height of the water level from the base falls to 26 cm.
- What is the capacity of Container L in litres?
- What is the volume of water in the container now in litres?
(a)
35 of Container L = 177615 mℓ
15 of Container L = 177615 ÷ 3 = 59205 mℓ
55 of Container L = 59205 x 5 = 296025 mℓ
1 ℓ = 1000 mℓ
Capacity of Container L = 296025 mℓ = 296.025 ℓ
(b)
Fraction of Container L not filled
= 1 -
35 =
25 Height of Container L not filled
=
25 x 70 cm
= 28 cm
Height of Container K
= 70 - 28 - 4
= 38 cm
Volume of remaining water in Container K
= 38 x 38 x 26
= 37544 cm
3 Volume of remaining water in Container L
= 70 x 70 x 26
= 127400 cm
3 Total volume of remaining water in the container
= 37544 + 127400
= 164944 cm
3
1 ℓ = 1000 cm
3 164944 cm
3 = 164.944 ℓ
Answer(s): (a) 296.025 ℓ; (b) 164.944 ℓ