The figure, not drawn to scale, is made of two connected cubical containers, M and N. Container M is sealed at the top and completely filled to the brim. Container N is ³₄ filled with 154386 mℓ of water. The height of the water level in Container N is 2 cm higher than that in Container M. Height of Container N is 70 cm. Water is then drained from the container and the height of the water level from the base falls to 40 cm.

1. What is the capacity of Container N in litres?
2. What is the volume of water in the container now in litres?

(a)
³₄ of Container N = 154386 mℓ
¹₄ of Container N = 154386 ÷ 3 = 51462 mℓ
⁴₄ of Container N = 51462 x 4 = 205848 mℓ

1 ℓ = 1000 mℓ

Capacity of Container N = 205848 mℓ = 205.848 ℓ

(b)
Fraction of Container N not filled
= 1 - ³₄
= ¹₄

Height of Container N not filled
= ¹₄ x 70 cm
= 17.5 cm

Height of Container M
= 70 - 17.5 - 2
= 50.5 cm

Volume of remaining water in Container M
= 50.5 x 50.5 x 40
= 102010 cm³ 

Volume of remaining water in Container N
= 70 x 70 x 40
= 196000 cm³ 

Total volume of remaining water in the container
= 102010 + 196000
= 298010 cm³

1 ℓ = 1000 cm³
298010 cm³ = 298.01 ℓ

Answer(s): (a) 205.848 ℓ; (b) 298.01 ℓ