The figure, not drawn to scale, is made of two connected cubical tanks, H and J. Tank H is sealed at the top and completely filled to the brim. Tank J is ²₅ filled with 108962 mℓ of water. The height of the water level in Tank J is 3 cm higher than that in Tank H. Height of Tank J is 65 cm. Water is then drained from the container and the height of the water level from the base falls to 23 cm.

1. What is the capacity of Tank J in litres?
2. What is the volume of water in the tank now in litres?

(a)
²₅ of Tank J = 108962 mℓ
¹₅ of Tank J = 108962 ÷ 2 = 54481 mℓ
⁵₅ of Tank J = 54481 x 5 = 272405 mℓ

1 ℓ = 1000 mℓ

Capacity of Tank J = 272405 mℓ = 272.405 ℓ

(b)
Fraction of Tank J not filled
= 1 - ²₅
= ³₅

Height of Tank J not filled
= ³₅ x 65 cm
= 39 cm

Height of Tank H
= 65 - 39 - 3
= 23 cm

Volume of remaining water in Tank H
= 23 x 23 x 23
= 12167 cm³ 

Volume of remaining water in Tank J
= 65 x 65 x 23
= 97175 cm³ 

Total volume of remaining water in the tank
= 12167 + 97175
= 109342 cm³

1 ℓ = 1000 cm³
109342 cm³ = 109.342 ℓ

Answer(s): (a) 272.405 ℓ; (b) 109.342 ℓ