The figure, not drawn to scale, is made of two connected cubical containers, T and U. Container T is sealed at the top and completely filled to the brim. Container U is ³₄ filled with 142860 mℓ of water. The height of the water level in Container U is 4 cm higher than that in Container T. Height of Container U is 58 cm. Water is then drained from the container and the height of the water level from the base falls to 20 cm.

1. What is the capacity of Container U in litres?
2. What is the volume of water in the container now in litres?

(a)
³₄ of Container U = 142860 mℓ
¹₄ of Container U = 142860 ÷ 3 = 47620 mℓ
⁴₄ of Container U = 47620 x 4 = 190480 mℓ

1 ℓ = 1000 mℓ

Capacity of Container U = 190480 mℓ = 190.48 ℓ

(b)
Fraction of Container U not filled
= 1 - ³₄
= ¹₄

Height of Container U not filled
= ¹₄ x 58 cm
= 14.5 cm

Height of Container T
= 58 - 14.5 - 4
= 39.5 cm

Volume of remaining water in Container T
= 39.5 x 39.5 x 20
= 31205 cm³ 

Volume of remaining water in Container U
= 58 x 58 x 20
= 67280 cm³ 

Total volume of remaining water in the container
= 31205 + 67280
= 98485 cm³

1 ℓ = 1000 cm³
98485 cm³ = 98.485 ℓ

Answer(s): (a) 190.48 ℓ; (b) 98.485 ℓ