The figure, not drawn to scale, is made of two connected cubical tanks, S and T. Tank S is sealed at the top and completely filled to the brim. Tank T is
34 filled with 184779 mℓ of water. The height of the water level in Tank T is 5 cm higher than that in Tank S. Height of Tank T is 64 cm. Water is then drained from the container and the height of the water level from the base falls to 30 cm.
- What is the capacity of Tank T in litres?
- What is the volume of water in the tank now in litres?
(a)
34 of Tank T = 184779 mℓ
14 of Tank T = 184779 ÷ 3 = 61593 mℓ
44 of Tank T = 61593 x 4 = 246372 mℓ
1 ℓ = 1000 mℓ
Capacity of Tank T = 246372 mℓ = 246.372 ℓ
(b)
Fraction of Tank T not filled
= 1 -
34 =
14 Height of Tank T not filled
=
14 x 64 cm
= 16 cm
Height of Tank S
= 64 - 16 - 5
= 43 cm
Volume of remaining water in Tank S
= 43 x 43 x 30
= 55470 cm
3 Volume of remaining water in Tank T
= 64 x 64 x 30
= 122880 cm
3 Total volume of remaining water in the tank
= 55470 + 122880
= 178350 cm
3
1 ℓ = 1000 cm
3 178350 cm
3 = 178.35 ℓ
Answer(s): (a) 246.372 ℓ; (b) 178.35 ℓ